orange 2x12 and 4x12
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If you had the same speaks, VIN30s for example, and both cabs were the same impedence, and you hit both cabs with the same power, I would expect the 4x12 to be slightly louder due to that elusive acoustic coupling thing. If you ran the calculation, one would not be louder than the other (assuming you stayed within the SPL range that a 2x12 could hit). The reality is there's a coupling phenom that reenforces more than the equation would suggest...
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I have a 2x12 stacked on a 4x12. The 2x12 is louder but it's also open back so I don't know how much of the difference is due to that. Both cabs use V30s.
<blockquote id="quote"><font size="1" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by pages plexitone</i>
<br />If you had the same speaks, VIN30s for example, and both cabs were the same impedence, and you hit both cabs with the same power, I would expect the 4x12 to be slightly louder due to that elusive acoustic coupling thing. If you ran the calculation, one would not be louder than the other (assuming you stayed within the SPL range that a 2x12 could hit). The reality is there's a coupling phenom that reenforces more than the equation would suggest...
<hr height="1" noshade id="quote"></font id="quote"></blockquote id="quote">
Assuming two 16ohm loads....
You're splitting the signal in parallel and sending it to two equal loads. One load consists of two speakers and the other load consists of four speakers. Therefore the two speaker load is recieving equal power to the four speaker load, and thus the two speakers will be driven harder.
<blockquote id="quote"><font size="1" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by pages plexitone</i>
<br />If you had the same speaks, VIN30s for example, and both cabs were the same impedence, and you hit both cabs with the same power, I would expect the 4x12 to be slightly louder due to that elusive acoustic coupling thing. If you ran the calculation, one would not be louder than the other (assuming you stayed within the SPL range that a 2x12 could hit). The reality is there's a coupling phenom that reenforces more than the equation would suggest...
<hr height="1" noshade id="quote"></font id="quote"></blockquote id="quote">
Assuming two 16ohm loads....
You're splitting the signal in parallel and sending it to two equal loads. One load consists of two speakers and the other load consists of four speakers. Therefore the two speaker load is recieving equal power to the four speaker load, and thus the two speakers will be driven harder.
Les Paul -> Wah -> Amp
Electric Amp 120w MV - Orange 4x12 + Electric 4x12
Electric Amp 120w MV - Orange 4x12 + Electric 4x12
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<blockquote id="quote"><font size="1" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by screamingdaisy</i>
<br />I have a 2x12 stacked on a 4x12. The 2x12 is louder but it's also open back so I don't know how much of the difference is due to that. Both cabs use V30s.
<blockquote id="quote"><font size="1" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by pages plexitone</i>
<br />If you had the same speaks, VIN30s for example, and both cabs were the same impedence, and you hit both cabs with the same power, I would expect the 4x12 to be slightly louder due to that elusive acoustic coupling thing. If you ran the calculation, one would not be louder than the other (assuming you stayed within the SPL range that a 2x12 could hit). The reality is there's a coupling phenom that reenforces more than the equation would suggest...
<hr height="1" noshade id="quote"></font id="quote"></blockquote id="quote">
Assuming two 16ohm loads....
You're splitting the signal in parallel and sending it to two equal loads. One load consists of two speakers and the other load consists of four speakers. Therefore the two speaker load is recieving equal power to the four speaker load, and thus the two speakers will be driven harder.
<hr height="1" noshade id="quote"></font id="quote"></blockquote id="quote">
Yep, the individual speaks in the 2x12 will be getting twice the juice that the speaks in the 4x12 are getting...the open back thing will make a heck of a difference in how it disperses etc.
So the equation
<br />I have a 2x12 stacked on a 4x12. The 2x12 is louder but it's also open back so I don't know how much of the difference is due to that. Both cabs use V30s.
<blockquote id="quote"><font size="1" face="Verdana, Arial, Helvetica" id="quote">quote:<hr height="1" noshade id="quote"><i>Originally posted by pages plexitone</i>
<br />If you had the same speaks, VIN30s for example, and both cabs were the same impedence, and you hit both cabs with the same power, I would expect the 4x12 to be slightly louder due to that elusive acoustic coupling thing. If you ran the calculation, one would not be louder than the other (assuming you stayed within the SPL range that a 2x12 could hit). The reality is there's a coupling phenom that reenforces more than the equation would suggest...
<hr height="1" noshade id="quote"></font id="quote"></blockquote id="quote">
Assuming two 16ohm loads....
You're splitting the signal in parallel and sending it to two equal loads. One load consists of two speakers and the other load consists of four speakers. Therefore the two speaker load is recieving equal power to the four speaker load, and thus the two speakers will be driven harder.
<hr height="1" noshade id="quote"></font id="quote"></blockquote id="quote">
Yep, the individual speaks in the 2x12 will be getting twice the juice that the speaks in the 4x12 are getting...the open back thing will make a heck of a difference in how it disperses etc.
So the equation
-Joe
http://soundclick.com/blackvelvetelvis" onclick="window.open(this.href);return false;
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